What is the derivative of 2^u ?

The derivative of 2^u is 2^uln(2)

What is the first derivative of 2^u ?

The first derivative of 2^u is 2^uln(2)

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derivative of

2^{u}

2^{u} ln (2)

Solution steps

\frac{d}{d u} (2^{u})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2^{u} ln (2)

\frac{1}{lo g _{3} ( 1 - 2 x )}

\frac{d}{d t} (t^{2} + t^{3})

\frac{d}{d t} (3 t^{2} - 5 cos^{3} (t))

\frac{d}{d x} (2 cos (3 x) + 2 sin (10 y) + 3 x - 10 y)

y = 1 - 2 x - x^{2}