What is the derivative of 3^x+2 ?

The derivative of 3^x+2 is ln(3)*3^x

What is the first derivative of 3^x+2 ?

The first derivative of 3^x+2 is ln(3)*3^x

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derivative of

3^{x} + 2

ln (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{x}) + \frac{d}{d x} (2)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

\frac{d}{d x} (2) = 0

= 3^{x} ln (3) + 0

Simplify

= ln (3) \cdot 3^{x}

lo g_{10} (\frac{2}{x})

\frac{( 3 x ^{2} - 1 ) ^{2}}{( x + 1 ) ^{3}}

t^{2} + 2 t + 4

(sin (x) + cos (x))^{3}

1 4^{x} + 16

What is the derivative of 3^x+2 ?
The derivative of 3^x+2 is ln(3)*3^x
What is the first derivative of 3^x+2 ?
The first derivative of 3^x+2 is ln(3)*3^x