What is the derivative of (2x^2-7)16w ?

The derivative of (2x^2-7)16w is 64xw

What is the first derivative of (2x^2-7)16w ?

The first derivative of (2x^2-7)16w is 64xw

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derivative of

(2 x^{2} - 7) 16 w

64 x w

Solution steps

\frac{d}{d x} ((2 x^{2} - 7) \cdot 16 w)

Treat

w

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 w \frac{d}{d x} (2 x^{2} - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 16 w (\frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (7))

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7) = 0

= 16 w (4 x - 0)

Simplify

= 64 x w

\frac{d}{d x} (i \cdot x \cdot 1 - 2 x)

4 x^{2} y + 1

3^{5 x^{2}}

\frac{d}{d t} (20 sin (2 t - 3 x))

y = 3 x^{7}

What is the derivative of (2x^2-7)16w ?
The derivative of (2x^2-7)16w is 64xw
What is the first derivative of (2x^2-7)16w ?
The first derivative of (2x^2-7)16w is 64xw