What is the derivative of y=sin(x^2+2x+3) ?

The derivative of y=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)

What is the first derivative of y=sin(x^2+2x+3) ?

The first derivative of y=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)

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derivative of

y = sin (x^{2} + 2 x + 3)

cos (x^{2} + 2 x + 3) (2 x + 2)

Solution steps

\frac{d}{d x} (sin (x^{2} + 2 x + 3))

Apply the chain rule:

cos (x^{2} + 2 x + 3) \frac{d}{d x} (x^{2} + 2 x + 3)

= cos (x^{2} + 2 x + 3) \frac{d}{d x} (x^{2} + 2 x + 3)

\frac{d}{d x} (x^{2} + 2 x + 3) = 2 x + 2

= cos (x^{2} + 2 x + 3) (2 x + 2)

\frac{d}{d b} (2 b)

\frac{d}{d o} (5^{c} os x)

\frac{d}{d t} (t^{2} + 5 t - 8)

t^{\frac{1}{4}}

s^{2} + 9

What is the derivative of y=sin(x^2+2x+3) ?
The derivative of y=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)
What is the first derivative of y=sin(x^2+2x+3) ?
The first derivative of y=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)