What is the derivative of 3ln(2x-1) ?

The derivative of 3ln(2x-1) is 6/(2x-1)

What is the first derivative of 3ln(2x-1) ?

The first derivative of 3ln(2x-1) is 6/(2x-1)

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derivative of

3 ln (2 x - 1)

\frac{6}{2 x - 1}

Solution steps

\frac{d}{d x} (3 ln (2 x - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (ln (2 x - 1))

Apply the chain rule:

\frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

= \frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 3 \cdot \frac{1}{2 x - 1} \cdot 2

Simplify

3 \cdot \frac{1}{2 x - 1} \cdot 2 : \frac{6}{2 x - 1}

= \frac{6}{2 x - 1}

\frac{( 3 x ^{2} + 5 ) ^{1}}{x}

y = x^{2} ln (4 x)

lo g_{10} (∣ 3 x ∣)

2^{3} x

y = x^{2} e^{2}

What is the derivative of 3ln(2x-1) ?
The derivative of 3ln(2x-1) is 6/(2x-1)
What is the first derivative of 3ln(2x-1) ?
The first derivative of 3ln(2x-1) is 6/(2x-1)