What is the d/(da)(3cos^2(a)-sin^2(a)) ?

The d/(da)(3cos^2(a)-sin^2(a)) is -4sin(2a)

What is the first d/(da)(3cos^2(a)-sin^2(a)) ?

The first d/(da)(3cos^2(a)-sin^2(a)) is -4sin(2a)

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\frac{d}{d a} (3 cos^{2} (a) - sin^{2} (a))

- 4 sin (2 a)

Solution steps

\frac{d}{d a} (3 cos^{2} (a) - sin^{2} (a))

Simplify

3 cos^{2} (a) - sin^{2} (a) : 3 - 4 sin^{2} (a)

= \frac{d}{d a} (3 - 4 sin^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (3) - \frac{d}{d a} (4 sin^{2} (a))

\frac{d}{d a} (3) = 0

\frac{d}{d a} (4 sin^{2} (a)) = 4 sin (2 a)

= 0 - 4 sin (2 a)

Simplify

= - 4 sin (2 a)

x tan (x) + 1

y = \frac{x + 2}{x ^{2}}

- 9 sin^{5} (x)

\frac{x ^{n + 1}}{( n + 1 )}

tan (lo g_{10} (x^{2}))

What is the d/(da)(3cos^2(a)-sin^2(a)) ?
The d/(da)(3cos^2(a)-sin^2(a)) is -4sin(2a)
What is the first d/(da)(3cos^2(a)-sin^2(a)) ?
The first d/(da)(3cos^2(a)-sin^2(a)) is -4sin(2a)