What is the derivative of 1/((s+3)^2) ?

The derivative of 1/((s+3)^2) is -2/((s+3)^3)

What is the first derivative of 1/((s+3)^2) ?

The first derivative of 1/((s+3)^2) is -2/((s+3)^3)

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derivative of

\frac{1}{( s + 3 ) ^{2}}

- \frac{2}{( s + 3 ) ^{3}}

Solution steps

\frac{d}{d s} (\frac{1}{( s + 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d s} ((s + 3)^{- 2})

Apply the chain rule:

- \frac{2}{( s + 3 ) ^{3}} \frac{d}{d s} (s + 3)

= - \frac{2}{( s + 3 ) ^{3}} \frac{d}{d s} (s + 3)

\frac{d}{d s} (s + 3) = 1

= - \frac{2}{( s + 3 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( s + 3 ) ^{3}}

2 x^{3} - 24 x^{1} - 35

4 x^{3} + 5

(x + 1)^{3} \cdot (5 - x)

\frac{1}{( 5 + x )}

y = (2 x + 1)^{s i n (5 x)}

What is the derivative of 1/((s+3)^2) ?
The derivative of 1/((s+3)^2) is -2/((s+3)^3)
What is the first derivative of 1/((s+3)^2) ?
The first derivative of 1/((s+3)^2) is -2/((s+3)^3)