What is the derivative of-2^x ?

The derivative of-2^x is -2^xln(2)

What is the first derivative of-2^x ?

The first derivative of-2^x is -2^xln(2)

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derivative of

- 2^{x}

- 2^{x} ln (2)

Solution steps

\frac{d}{d x} (- 2^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= - 2^{x} ln (2)

\frac{1}{4} \cdot x^{2} - \frac{( sin ( 2 x ^{2} ) )}{8}

sin^{4} (3 x - 4 x^{2})

y = \frac{x ^{7} + 1}{x}

- (e^{- x})^{2}

lo g_{10} (x - 1)