What is the derivative of f(x)=x^2-4x+9 ?

The derivative of f(x)=x^2-4x+9 is 2x-4

What is the first derivative of f(x)=x^2-4x+9 ?

The first derivative of f(x)=x^2-4x+9 is 2x-4

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derivative of

f (x) = x^{2} - 4 x + 9

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (9) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

e^{x} - y^{2}

\frac{d}{d t} (10 + 5 t)

\frac{2000}{x}

\frac{( x ^{2} + 2 x )}{( x + 1 )}

(3 x^{- 2} x) (e^{x} - sin (x))

What is the derivative of f(x)=x^2-4x+9 ?
The derivative of f(x)=x^2-4x+9 is 2x-4
What is the first derivative of f(x)=x^2-4x+9 ?
The first derivative of f(x)=x^2-4x+9 is 2x-4