What is the first derivative of 3t+4 ?

The first derivative of 3t+4 is 3

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derivative of 3t+4

derivative of

3 t + 4

3

Solution steps

\frac{d}{d t} (3 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t) + \frac{d}{d t} (4)

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (4) = 0

= 3 + 0

Simplify

= 3

3 t - 1

\frac{3}{x ^{2} + 2}

\frac{d}{d z} (z^{3} + i)

\frac{3 x}{5}

\frac{t ^{3}}{( 1 - 3 t ^{3} )}