What is the d/(dq)(5-|2q-3|) ?

The d/(dq)(5-|2q-3|) is -(2(2q-3))/(|2q-3|)

What is the first d/(dq)(5-|2q-3|) ?

The first d/(dq)(5-|2q-3|) is -(2(2q-3))/(|2q-3|)

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\frac{d}{d q} (5 - ∣ 2 q - 3 ∣)

- \frac{2 ( 2 q - 3 )}{∣ 2 q - 3 ∣}

Solution steps

\frac{d}{d q} (5 - ∣ 2 q - 3 ∣)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (5) - \frac{d}{d q} (∣ 2 q - 3 ∣)

\frac{d}{d q} (5) = 0

\frac{d}{d q} (∣ 2 q - 3 ∣) = \frac{2 ( 2 q - 3 )}{∣ 2 q - 3 ∣}

= 0 - \frac{2 ( 2 q - 3 )}{∣ 2 q - 3 ∣}

Simplify

= - \frac{2 ( 2 q - 3 )}{∣ 2 q - 3 ∣}

(x + 5)^{- 1}

(e^{x})^{\frac{1}{3}}

\frac{1}{( s ^{2} + 2 )}

\frac{d}{d x} (lo g_{10} (1 + x^{2} y^{2}))

\frac{d}{d t} (t^{3} - 6 t^{2} + 9 t)

What is the d/(dq)(5-|2q-3|) ?
The d/(dq)(5-|2q-3|) is -(2(2q-3))/(|2q-3|)
What is the first d/(dq)(5-|2q-3|) ?
The first d/(dq)(5-|2q-3|) is -(2(2q-3))/(|2q-3|)