What is the derivative of (1+x)^{2y+1} ?

The derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}

What is the first derivative of (1+x)^{2y+1} ?

The first derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}

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derivative of

(1 + x)^{2 y + 1}

(2 y + 1) (1 + x)^{2 y}

Solution steps

\frac{d}{d x} ((1 + x)^{2 y + 1})

Treat

y

as a constant

Apply the chain rule:

(1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

= (1 + x)^{2 y} (2 y + 1) \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= (1 + x)^{2 y} (2 y + 1) \cdot 1

Simplify

= (2 y + 1) (1 + x)^{2 y}

y = (sin (x))^{5}

(2^{x})^{2} + 1 + e^{c} os x

g (x) = 2 x + 2

sin^{4} (3 x)

(\frac{16}{x})^{^{'}}

What is the derivative of (1+x)^{2y+1} ?
The derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}
What is the first derivative of (1+x)^{2y+1} ?
The first derivative of (1+x)^{2y+1} is (2y+1)(1+x)^{2y}