What is the derivative of 2x^2+x+5 ?

The derivative of 2x^2+x+5 is 4x+1

What is the first derivative of 2x^2+x+5 ?

The first derivative of 2x^2+x+5 is 4x+1

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derivative of

2 x^{2} + x + 5

4 x + 1

Solution steps

\frac{d}{d x} (2 x^{2} + x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 4 x + 1 + 0

Simplify

= 4 x + 1

x^{2} lo g_{10} (\frac{1}{x})

\frac{1}{( 1 - x ^{2} )}

sin (x) + ln (x^{2}) + e^{2} x

6 x^{\frac{1}{3}}

(\frac{x ^{5} + 1}{x}) (x^{5} + 1)

What is the derivative of 2x^2+x+5 ?
The derivative of 2x^2+x+5 is 4x+1
What is the first derivative of 2x^2+x+5 ?
The first derivative of 2x^2+x+5 is 4x+1