What is the derivative of sec^2(3x^2-7x+4) ?

The derivative of sec^2(3x^2-7x+4) is 2sec^2(3x^2-7x+4)tan(3x^2-7x+4)(6x-7)

What is the first derivative of sec^2(3x^2-7x+4) ?

The first derivative of sec^2(3x^2-7x+4) is 2sec^2(3x^2-7x+4)tan(3x^2-7x+4)(6x-7)

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derivative of

sec^{2} (3 x^{2} - 7 x + 4)

2 sec^{2} (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7)

Solution steps

\frac{d}{d x} (sec^{2} (3 x^{2} - 7 x + 4))

Apply the chain rule:

2 sec (3 x^{2} - 7 x + 4) \frac{d}{d x} (sec (3 x^{2} - 7 x + 4))

= 2 sec (3 x^{2} - 7 x + 4) \frac{d}{d x} (sec (3 x^{2} - 7 x + 4))

\frac{d}{d x} (sec (3 x^{2} - 7 x + 4)) = sec (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7)

= 2 sec (3 x^{2} - 7 x + 4) sec (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7)

Simplify

2 sec (3 x^{2} - 7 x + 4) sec (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7) : 2 sec^{2} (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7)

= 2 sec^{2} (3 x^{2} - 7 x + 4) tan (3 x^{2} - 7 x + 4) (6 x - 7)

y = (x + 2) (x^{2} + 1)

h (x) = \frac{5}{6 x ^{5}}

(sin (x^{3} - 4 x + 2))^{^{'}}

(\frac{x + 1}{x}) + 5

\frac{- 2 x}{5}

What is the derivative of sec^2(3x^2-7x+4) ?
The derivative of sec^2(3x^2-7x+4) is 2sec^2(3x^2-7x+4)tan(3x^2-7x+4)(6x-7)
What is the first derivative of sec^2(3x^2-7x+4) ?
The first derivative of sec^2(3x^2-7x+4) is 2sec^2(3x^2-7x+4)tan(3x^2-7x+4)(6x-7)