What is the derivative of 1/((z-1)) ?

The derivative of 1/((z-1)) is -1/((z-1)^2)

What is the first derivative of 1/((z-1)) ?

The first derivative of 1/((z-1)) is -1/((z-1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{( z - 1 )}

- \frac{1}{( z - 1 ) ^{2}}

Solution steps

\frac{d}{d z} (\frac{1}{z - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d z} ((z - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( z - 1 ) ^{2}} \frac{d}{d z} (z - 1)

= - \frac{1}{( z - 1 ) ^{2}} \frac{d}{d z} (z - 1)

\frac{d}{d z} (z - 1) = 1

= - \frac{1}{( z - 1 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( z - 1 ) ^{2}}

y = 25

sin^{35} (x)

\frac{d}{d t} (4 + 12 t + 8 t^{2})

\frac{ln ( x + 1 )}{x}

\frac{d}{d x} ((\frac{x}{( y + z )})^{2})

What is the derivative of 1/((z-1)) ?
The derivative of 1/((z-1)) is -1/((z-1)^2)
What is the first derivative of 1/((z-1)) ?
The first derivative of 1/((z-1)) is -1/((z-1)^2)