What is the derivative of f(x)=2cos(2x-1) ?

The derivative of f(x)=2cos(2x-1) is -4sin(2x-1)

What is the first derivative of f(x)=2cos(2x-1) ?

The first derivative of f(x)=2cos(2x-1) is -4sin(2x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 2 cos (2 x - 1)

- 4 sin (2 x - 1)

Solution steps

\frac{d}{d x} (2 cos (2 x - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x - 1))

Apply the chain rule:

- sin (2 x - 1) \frac{d}{d x} (2 x - 1)

= - sin (2 x - 1) \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 2 (- sin (2 x - 1) \cdot 2)

Simplify

= - 4 sin (2 x - 1)

\frac{- 1}{sin ^{2} ( x )}

\frac{d}{d v} (\frac{( v - 0 )}{t})

f (x) = 2 e^{2 x - 3}

lo g_{10} (\frac{2}{( 2 x + 2 )})

x + 6

What is the derivative of f(x)=2cos(2x-1) ?
The derivative of f(x)=2cos(2x-1) is -4sin(2x-1)
What is the first derivative of f(x)=2cos(2x-1) ?
The first derivative of f(x)=2cos(2x-1) is -4sin(2x-1)