What is derivative of (d^2+1)*y=x^2*(cos(x)) ?

The answer to derivative of (d^2+1)*y=x^2*(cos(x)) is (dy)/(dx)=(2xcos(x)-x^2sin(x))/(d^2+1)

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derivative of (d^2+1)y=x^2(cos(x))

derivative of

(d^{2} + 1) \cdot y = x^{2} \cdot (cos (x))

\frac{d y}{d x} = \frac{2 x cos ( x ) - x ^{2} sin ( x )}{d ^{2} + 1}

Solution steps

(d^{2} + 1) y = x^{2} cos (x)

Treat

y

y (x)

Differentiate both sides:

(d^{2} + 1) \frac{d y}{d x} = 2 x cos (x) - x^{2} sin (x)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 x cos ( x ) - x ^{2} sin ( x )}{d ^{2} + 1}

\frac{d y}{d x} = \frac{2 x cos ( x ) - x ^{2} sin ( x )}{d ^{2} + 1}

x^{3} + y^{3} = 9

x^{2} + y^{2} - 3 x y = 1

7 x^{4} - 4 y = 4

4 x + 5 y = lo g_{10} (4 x - 3 y)

x^{4} + y^{4} = x^{2} y^{2}

What is derivative of (d^2+1)*y=x^2*(cos(x)) ?
The answer to derivative of (d^2+1)*y=x^2*(cos(x)) is (dy)/(dx)=(2xcos(x)-x^2sin(x))/(d^2+1)