What is derivative of 4y=-8x+2x+0 ?

The answer to derivative of 4y=-8x+2x+0 is (dy)/(dx)=-3/2

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derivative of 4y=-8x+2x+0

derivative of

4 y = - 8 x + 2 x + 0

\frac{d y}{d x} = - \frac{3}{2}

Solution steps

4 y = - 8 x + 2 x + 0

Treat

y

y (x)

Differentiate both sides:

4 \frac{d y}{d x} = - 6

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{3}{2}

\frac{d y}{d x} = - \frac{3}{2}

y^{2} = x

x^{2} + y^{2} = 6 x + 4 y

x = \frac{u - 1}{2}

x = y^{2}

x^{2} + x y + 42 = 100

What is derivative of 4y=-8x+2x+0 ?
The answer to derivative of 4y=-8x+2x+0 is (dy)/(dx)=-3/2