What is derivative of sin(y)+cos(x)=1 ?

The answer to derivative of sin(y)+cos(x)=1 is (dy)/(dx)=(sin(x))/(cos(y))

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derivative of sin(y)+cos(x)=1

derivative of

sin (y) + cos (x) = 1

\frac{d y}{d x} = \frac{sin ( x )}{cos ( y )}

Solution steps

sin (y) + cos (x) = 1

Treat

y

y (x)

Differentiate both sides:

cos (y) \frac{d y}{d x} - sin (x) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{sin ( x )}{cos ( y )}

\frac{d y}{d x} = \frac{sin ( x )}{cos ( y )}

x^{2} + y^{2} - 2 x = 1

p = 7 q^{3} (5 q - 150)

x^{2} + x y + y^{2} = 4

e^{x} y = 2 y

y^{3} - 3 x y^{2} = x^{3} + 3 x^{2} y

What is derivative of sin(y)+cos(x)=1 ?
The answer to derivative of sin(y)+cos(x)=1 is (dy)/(dx)=(sin(x))/(cos(y))