What is derivative of x^2+y^2=1 ?

The answer to derivative of x^2+y^2=1 is (dy)/(dx)=-x/y

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derivative of x^2+y^2=1

derivative of

x^{2} + y^{2} = 1

\frac{d y}{d x} = - \frac{x}{y}

Solution steps

x^{2} + y^{2} = 1

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x}{y}

\frac{d y}{d x} = - \frac{x}{y}

2 x + 25 y = 0

x^{2} y + y^{2} x = 6

x^{2} (x - 2 y) = x + 2 y

p = i^{2} r

x (x + i) + y (y - i) + i = 13

What is derivative of x^2+y^2=1 ?
The answer to derivative of x^2+y^2=1 is (dy)/(dx)=-x/y