What is derivative of 2x^2+2y-2xy=4 ?

The answer to derivative of 2x^2+2y-2xy=4 is (dy)/(dx)=(-2x+y)/(1-x)

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derivative of 2x^2+2y-2xy=4

derivative of

2 x^{2} + 2 y - 2 x y = 4

\frac{d y}{d x} = \frac{- 2 x + y}{1 - x}

Solution steps

2 x^{2} + 2 y - 2 x y = 4

Treat

y

y (x)

Differentiate both sides:

4 x + 2 \frac{d y}{d x} - 2 (y + x \frac{d y}{d x}) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 2 x + y}{1 - x}

\frac{d y}{d x} = \frac{- 2 x + y}{1 - x}

x^{2} + 2 x y = y^{2}

x^{3} + x^{2} y + 7 x y^{2} + y^{3} = 81

y - 4 = 2 (x - 1)^{2}

y^{2} x^{3} + x^{2} + y = 7

sin^{2} (y) + cos (x) y = k

What is derivative of 2x^2+2y-2xy=4 ?
The answer to derivative of 2x^2+2y-2xy=4 is (dy)/(dx)=(-2x+y)/(1-x)