What is derivative of 2x^3+4x^2-y=x^6 ?

The answer to derivative of 2x^3+4x^2-y=x^6 is (dy)/(dx)=-6x^5+6x^2+8x

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derivative of 2x^3+4x^2-y=x^6

derivative of

2 x^{3} + 4 x^{2} - y = x^{6}

\frac{d y}{d x} = - 6 x^{5} + 6 x^{2} + 8 x

Solution steps

2 x^{3} + 4 x^{2} - y = x^{6}

Treat

y

y (x)

Differentiate both sides:

6 x^{2} + 8 x - \frac{d y}{d x} = 6 x^{5}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - 6 x^{5} + 6 x^{2} + 8 x

\frac{d y}{d x} = - 6 x^{5} + 6 x^{2} + 8 x

y + 5 i = (2 x + i) (x + 2 i)

x = 70 y - y^{2}

2 y^{3} x + x^{3} = y^{5} + 12

x^{2} + y^{2} + 10 y = 4

(e^{x})^{2}

What is derivative of 2x^3+4x^2-y=x^6 ?
The answer to derivative of 2x^3+4x^2-y=x^6 is (dy)/(dx)=-6x^5+6x^2+8x