What is the solution for (dy)/(dt)+20y=24 ?

The solution for (dy)/(dt)+20y=24 is y=-(e^{-20t-c_{1}})/5+6/5

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(dy)/(dt)+20y=24

\frac{d y}{d t} + 20 y = 24

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

Solution steps

\frac{d y}{d t} + 20 y = 24

Solve separable ODE:

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

y = - \frac{e ^{- 20 t - c_{1}}}{5} + \frac{6}{5}

\int 4 θ sec^{2} (θ) d θ

y^{^{'}} = - \frac{y ^{2}}{( 0.05 + y )}, y (0) = 9

\int \frac{1}{2} x^{\frac{3}{4}} d x

\int (9) d x

y = x^{2} + 19 x^{9}

What is the solution for (dy)/(dt)+20y=24 ?
The solution for (dy)/(dt)+20y=24 is y=-(e^{-20t-c_{1}})/5+6/5