What is the integral of (e^x)/2 ?

The integral of (e^x)/2 is 1/2 e^x+C

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integral of (e^x)/2

integral

\frac{e ^{x}}{2}

\frac{1}{2} e^{x} + C

Solution steps

\int \frac{e ^{x}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= \frac{1}{2} e^{x}

Add a constant to the solution

= \frac{1}{2} e^{x} + C

1 + x

\frac{1}{( 1 + x )}

1 - cos^{2} (x)

(e^{x})^{3}

\frac{1}{( x ^{3} - 1 )}