What is the integral of sin(2-4x) ?

The integral of sin(2-4x) is 1/4 cos(2-4x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(2-4x)

integral

sin (2 - 4 x)

\frac{1}{4} cos (2 - 4 x) + C

Solution steps

\int sin (2 - 4 x) d x

Apply u-substitution

: \int - \frac{1}{4} sin (u) d u

= \int - \frac{1}{4} sin (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - \frac{1}{4} (- cos (u))

Substitute back

u = 2 - 4 x

= - \frac{1}{4} (- cos (2 - 4 x))

Simplify

= \frac{1}{4} cos (2 - 4 x)

Add a constant to the solution

= \frac{1}{4} cos (2 - 4 x) + C

\frac{x}{( x ^{2} + a ^{2} )}

\frac{1}{( x - 1 )}

x^{3} (e^{x})^{2}

\frac{1}{( x ^{3} + 1 )}

\frac{( x - 1 )}{( x + 1 ) ^{2}}

What is the integral of sin(2-4x) ?
The integral of sin(2-4x) is 1/4 cos(2-4x)+C