What is the integral of (-2)/(x^2) ?

The integral of (-2)/(x^2) is 2/x+C

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integral of (-2)/(x^2)

integral

\frac{- 2}{x ^{2}}

\frac{2}{x} + C

Solution steps

\int \frac{- 2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 2 (- \frac{1}{x})

Simplify

- 2 (- \frac{1}{x}) : \frac{2}{x}

= \frac{2}{x}

Add a constant to the solution

= \frac{2}{x} + C

\frac{2}{e ^{x}}

t^{2} + 1

\frac{x ^{2}}{( x ^{2} - 1 )}

cos (\frac{1}{x})

\frac{x + 1}{x}