What is the integral of sin^2(x)sin^3(x) ?

The integral of sin^2(x)sin^3(x) is -cos(x)+(2cos^3(x))/3-(cos^5(x))/5+C

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integral of sin^2(x)sin^3(x)

integral

sin^{2} (x) sin^{3} (x)

- cos (x) + \frac{2 cos ^{3} ( x )}{3} - \frac{cos ^{5} ( x )}{5} + C

Solution steps

\int sin^{2} (x) sin^{3} (x) d x

Simplify

sin^{2} (x) sin^{3} (x) : sin^{5} (x)

= \int sin^{5} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x))^{2} sin (x) d x

Apply u-substitution

: \int - 1 + 2 u^{2} - u^{4} d u

= \int - 1 + 2 u^{2} - u^{4} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d u + \int 2 u^{2} d u - \int u^{4} d u

\int 1 d u = u

\int 2 u^{2} d u = \frac{2 u ^{3}}{3}

\int u^{4} d u = \frac{u ^{5}}{5}

= - u + \frac{2 u ^{3}}{3} - \frac{u ^{5}}{5}

Substitute back

u = cos (x)

= - cos (x) + \frac{2 cos ^{3} ( x )}{3} - \frac{cos ^{5} ( x )}{5}

Add a constant to the solution

= - cos (x) + \frac{2 cos ^{3} ( x )}{3} - \frac{cos ^{5} ( x )}{5} + C

\frac{sin ^{2} ( x )}{2}

e^{x^{2} + x}

sin^{3} (x) sin^{3} (x)

(e^{x} + e^{- x})^{2}

\frac{1}{( e ^{x} + e ^{- x} )}

What is the integral of sin^2(x)sin^3(x) ?
The integral of sin^2(x)sin^3(x) is -cos(x)+(2cos^3(x))/3-(cos^5(x))/5+C