What is the tangent of f(x)= 1/x ,(2, 1/2) ?

The tangent of f(x)= 1/x ,(2, 1/2) is y=-1/4 x+1

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tangent of f(x)= 1/x ,(2, 1/2)

tangent of

f (x) = \frac{1}{x}, (2, \frac{1}{2})

y = - \frac{1}{4} x + 1

Solution steps

Find the slope of

f (x) = \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

f (x) = \frac{1}{x}

(2, \frac{1}{2}) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(2, \frac{1}{2}) : y = - \frac{1}{4} x + 1

y = - \frac{1}{4} x + 1

\frac{d}{d x} ((x^{3} + x^{2} - 2) (7 + x - x^{4}))

\int \frac{( 3 ( 4 u + 1 ) ^{\frac{1}{2}} )}{4} d u

\frac{d}{d x} (3 arccos (\frac{x}{2}))

\int \frac{42 w ^{7} - 7 w}{7 w ^{5}} d w

x \to 2 lim (\frac{x ^{3} - 8}{x + 2})

What is the tangent of f(x)= 1/x ,(2, 1/2) ?
The tangent of f(x)= 1/x ,(2, 1/2) is y=-1/4 x+1