What is the integral of e^{x+1} ?

The integral of e^{x+1} is e^{1+x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{x+1}

integral

e^{x + 1}

e^{1 + x} + C

Solution steps

\int e^{x + 1} d x

e^{x + 1} = e^{1} e^{x}

= \int e^{1} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{1} \cdot \int e^{x} d x

Simplify

= e \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= e e^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e e^{x} = e^{1 + x}

= e^{1 + x}

Add a constant to the solution

= e^{1 + x} + C

x^{5} (x^{2} + 3)^{4}

- 3 x^{- 4}

cos (x^{2} + 1)

(4 + x)^{\frac{1}{2}}

x^{2} + 2 x + 3