What is the integral of 1/((1+y^2)) ?

The integral of 1/((1+y^2)) is arctan(y)+C

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integral of 1/((1+y^2))

integral

\frac{1}{( 1 + y ^{2} )}

arctan (y) + C

Solution steps

\int \frac{1}{1 + y ^{2}} d y

Use the common integral:

\int \frac{1}{1 + y ^{2}} d y = arctan (y)

= arctan (y)

Add a constant to the solution

= arctan (y) + C

\frac{1}{( 1 + 2 x ^{2} )}

e^{- 4} x

\frac{4 x}{( x ^{2} + 1 )}

cosh^{2} (x)

1 - cot^{2} (x)

What is the integral of 1/((1+y^2)) ?
The integral of 1/((1+y^2)) is arctan(y)+C