What is the integral of tan^3(x)sec^3(x) ?

The integral of tan^3(x)sec^3(x) is (sec^5(x))/5-(sec^3(x))/3+C

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integral of tan^3(x)sec^3(x)

integral

tan^{3} (x) sec^{3} (x)

\frac{sec ^{5} ( x )}{5} - \frac{sec ^{3} ( x )}{3} + C

Solution steps

\int tan^{3} (x) sec^{3} (x) d x

Rewrite using trig identities

= \int (- 1 + sec^{2} (x)) tan (x) sec^{3} (x) d x

Apply u-substitution

: \int u^{2} (u^{2} - 1) d u

= \int u^{2} (u^{2} - 1) d u

Expand

u^{2} (u^{2} - 1) : u^{4} - u^{2}

= \int u^{4} - u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{4} d u - \int u^{2} d u

\int u^{4} d u = \frac{u ^{5}}{5}

\int u^{2} d u = \frac{u ^{3}}{3}

= \frac{u ^{5}}{5} - \frac{u ^{3}}{3}

Substitute back

u = sec (x)

= \frac{sec ^{5} ( x )}{5} - \frac{sec ^{3} ( x )}{3}

Add a constant to the solution

= \frac{sec ^{5} ( x )}{5} - \frac{sec ^{3} ( x )}{3} + C

x + 5

(1 - x)^{\frac{1}{2}}

x^{2} cos^{2} (x)

sin (t^{2})

\frac{1}{( x ^{2} + 2 x )}

What is the integral of tan^3(x)sec^3(x) ?
The integral of tan^3(x)sec^3(x) is (sec^5(x))/5-(sec^3(x))/3+C