What is the solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 ?

The solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 is y=2e^{-t}t

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y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{- t}, y (0) = 0, y^{^{'}} (0) = 2

y = 2 e^{- t} t

Solution steps

y^{''} (t) + 4 y^{'} (t) + 3 y = 4 e^{- t}

Solve linear ODE:

y = 2 e^{- t} t

y = 2 e^{- t} t

\frac{d}{d x} (\frac{1}{sin ( x )})

f (x) = ln (5)

\int \frac{1}{5 s + 4} d s

x \to + 3 lim (3 x^{2} + 4 x - 1)

x \to 6 lim (4 x)

What is the solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 ?
The solution for y^{''}+4y^'+3y=4e^{-t},y(0)=0,y^'(0)=2 is y=2e^{-t}t