What is the integral of (cos^3(x))/(sin(x)) ?

The integral of (cos^3(x))/(sin(x)) is ln|sin(x)|-(sin^2(x))/2+C

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integral of (cos^3(x))/(sin(x))

integral

\frac{cos ^{3} ( x )}{sin ( x )}

ln ∣ sin (x) ∣ - \frac{sin ^{2} ( x )}{2} + C

Solution steps

\int \frac{cos ^{3} ( x )}{sin ( x )} d x

Rewrite using trig identities

= \int \frac{( 1 - sin ^{2} ( x ) ) cos ( x )}{sin ( x )} d x

Apply u-substitution

: \int \frac{1 - u ^{2}}{u} d u

= \int \frac{1 - u ^{2}}{u} d u

Expand

\frac{1 - u ^{2}}{u} : \frac{1}{u} - u

= \int \frac{1}{u} - u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{u} d u - \int u d u

\int \frac{1}{u} d u = ln ∣ u ∣

\int u d u = \frac{u ^{2}}{2}

= ln ∣ u ∣ - \frac{u ^{2}}{2}

Substitute back

u = sin (x)

= ln ∣ sin (x) ∣ - \frac{sin ^{2} ( x )}{2}

Add a constant to the solution

= ln ∣ sin (x) ∣ - \frac{sin ^{2} ( x )}{2} + C

\frac{x}{2 + 3}

(e^{- y})^{2}

\frac{1}{( 2 x + 3 )}

2 t + 1

\frac{x ^{2} - 1}{x}

What is the integral of (cos^3(x))/(sin(x)) ?
The integral of (cos^3(x))/(sin(x)) is ln|sin(x)|-(sin^2(x))/2+C