What is the integral of 1/(x^{1/2)} ?

The integral of 1/(x^{1/2)} is 2x^{1/2}+C

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integral of 1/(x^{1/2)}

integral

\frac{1}{x ^{\frac{1}{2}}}

2 x^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Add a constant to the solution

= 2 x^{\frac{1}{2}} + C

y = x^{2}

\frac{x}{( 1 + x ^{3} )}

\frac{e ^{x}}{( e ^{x} + 1 ) ^{2}}

\frac{x ^{2}}{( x - 1 )}

x^{2} a^{2} + x^{2}