What is the integral of ((x^2))/3 ?

The integral of ((x^2))/3 is (x^3)/9+C

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integral of ((x^2))/3

integral

\frac{( x ^{2} )}{3}

\frac{x ^{3}}{9} + C

Solution steps

\int \frac{x ^{2}}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{1}{3} \cdot \frac{x ^{3}}{3}

Simplify

\frac{1}{3} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{9}

= \frac{x ^{3}}{9}

Add a constant to the solution

= \frac{x ^{3}}{9} + C

\frac{x}{( 0.5 x - 1 ) ^{0.5}}

\frac{x}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

\frac{1}{( 2 x ^{2} )}

2 e^{\frac{- x}{3}}

\frac{1}{x ^{3} y ^{2}}