What is the integral of ((e^x+e^{-x}))/2 ?

The integral of ((e^x+e^{-x}))/2 is sinh(x)+C

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integral of ((e^x+e^{-x}))/2

integral

\frac{( e ^{x} + e ^{- x} )}{2}

sinh (x) + C

Solution steps

\int \frac{e ^{x} + e ^{- x}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{x} + e^{- x} d x

Rewrite using trig identities

= \frac{1}{2} \cdot \int 2 cosh (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot 2 \cdot \int cosh (x) d x

Use the common integral:

\int cosh (x) d x = sinh (x)

= \frac{1}{2} \cdot 2 sinh (x)

Simplify

\frac{1}{2} \cdot 2 sinh (x) : sinh (x)

= sinh (x)

Add a constant to the solution

= sinh (x) + C

\frac{2 x}{( x ^{2} + 1 ) ^{2}}

y^{2} x^{3}

\frac{1}{( x ^{2} - 3 )}

lo g_{10} (x^{2} + y^{2})

\frac{( 1 - x ^{2} )}{( 1 + x ^{2} )}

What is the integral of ((e^x+e^{-x}))/2 ?
The integral of ((e^x+e^{-x}))/2 is sinh(x)+C