What is the integral of 3/((x^2+1)) ?

The integral of 3/((x^2+1)) is 3arctan(x)+C

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integral of 3/((x^2+1))

integral

\frac{3}{( x ^{2} + 1 )}

3 arctan (x) + C

Solution steps

\int \frac{3}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 3 arctan (x)

Add a constant to the solution

= 3 arctan (x) + C

1 3^{x} + 1

arctan (x + 1)

\frac{1}{s ^{3}}

x^{2} + 8 x - 3

\frac{( 1 + x )}{x}

What is the integral of 3/((x^2+1)) ?
The integral of 3/((x^2+1)) is 3arctan(x)+C