What is the integral of ((1+x))/((1-x)) ?

The integral of ((1+x))/((1-x)) is -2ln|1-x|-x+C

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integral of ((1+x))/((1-x))

integral

\frac{( 1 + x )}{( 1 - x )}

- 2 ln ∣ 1 - x ∣ - x + C

Solution steps

\int \frac{1 + x}{1 - x} d x

\frac{1 + x}{1 - x} = \frac{2}{1 - x} - 1

= \int \frac{2}{1 - x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{1 - x} d x - \int 1 d x

\int \frac{2}{1 - x} d x = - 2 ln ∣ 1 - x ∣

\int 1 d x = x

= - 2 ln ∣ 1 - x ∣ - x

Add a constant to the solution

= - 2 ln ∣ 1 - x ∣ - x + C

\frac{1}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

ln (x - 2)

\frac{v}{( 2 v - 1 )}

\frac{1}{( 1 + e ^{x} )}

\frac{( e ^{- x} ) ^{2}}{x}

What is the integral of ((1+x))/((1-x)) ?
The integral of ((1+x))/((1-x)) is -2ln|1-x|-x+C