What is the integral of 2e^{-2x} ?

The integral of 2e^{-2x} is -e^{-2x}+C

Popular >

integral of 2e^{-2x}

integral

2 e^{- 2 x}

- e^{- 2 x} + C

Solution steps

\int 2 e^{- 2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{- 2 x} d x

Apply u-substitution

: \int - \frac{1}{2} e^{u} d u

= 2 \cdot \int - \frac{1}{2} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \frac{1}{2} \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 2 (- \frac{1}{2} e^{u})

Substitute back

u = - 2 x

= 2 (- \frac{1}{2} e^{- 2 x})

Simplify

2 (- \frac{1}{2} e^{- 2 x}) : - e^{- 2 x}

= - e^{- 2 x}

Add a constant to the solution

= - e^{- 2 x} + C

\frac{1}{( x )}

\frac{x ^{2}}{( 1 + x ^{3} )}

\frac{1}{1 + ( 7 x + 6 ) ^{2}}

\frac{( 2 x - 1 )}{x ^{3}}

y = 7 x^{5}