What is the integral of e^{-x-3} ?

The integral of e^{-x-3} is -e^{-x-3}+C

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integral of e^{-x-3}

integral

e^{- x - 3}

- e^{- x - 3} + C

Solution steps

\int e^{- x - 3} d x

Apply u-substitution

: \int - e^{u} d u

= \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - e^{u}

Substitute back

u = - x - 3

= - e^{- x - 3}

Add a constant to the solution

= - e^{- x - 3} + C

r^{3}

\frac{x}{( x + 3 )}

sin (t) cos^{2} (t)

1 + 4 x^{2}

tan^{3} (x) + tan (x)