What is (\partial)/(\partial x)(-y-x/(y^2)) ?

The answer to (\partial)/(\partial x)(-y-x/(y^2)) is -1/(y^2)

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(\partial)/(\partial x)(-y-x/(y^2))

\frac{\partial}{\partial x} (- y - \frac{x}{y ^{2}})

- \frac{1}{y ^{2}}

Solution steps

\frac{\partial}{\partial x} (- y - \frac{x}{y ^{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (\frac{x}{y ^{2}})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (\frac{x}{y ^{2}}) = \frac{1}{y ^{2}}

= - 0 - \frac{1}{y ^{2}}

Simplify

= - \frac{1}{y ^{2}}

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What is (\partial)/(\partial x)(-y-x/(y^2)) ?
The answer to (\partial)/(\partial x)(-y-x/(y^2)) is -1/(y^2)