What is the f(x)=(x^2+2x+5)^{1/2} ?

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f(x)=(x^2+2x+5)^{1/2}

f (x) = (x^{2} + 2 x + 5)^{\frac{1}{2}}

Domain : - \infty < x < \infty

Range : f (x) \geq 2

Y Intercepts : (0, 5^{\frac{1}{2}})

Asymptotes : None

Extreme Points : Minimum (- 1, 2)

Interval Notation

Domain : (- \infty, \infty)

Range : [2, \infty)

Solution steps

Domain of

(x^{2} + 2 x + 5)^{\frac{1}{2}} : - \infty < x < \infty

Range of

(x^{2} + 2 x + 5)^{\frac{1}{2}} : f (x) \geq 2

Axis interception points of

(x^{2} + 2 x + 5)^{\frac{1}{2}} :

Y Intercepts

: (0, 5^{\frac{1}{2}})

Asymptotes of

(x^{2} + 2 x + 5)^{\frac{1}{2}} :

None

Extreme Points of

(x^{2} + 2 x + 5)^{\frac{1}{2}} :

Minimum

(- 1, 2)

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