What is the integral of ((x^4)/(12))^2 ?

The integral of ((x^4)/(12))^2 is (x^9)/(144)-(x^9)/(162)+C

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integral of ((x^4)/(12))^2

integral

(\frac{x ^{4}}{12})^{2}

\frac{x ^{9}}{144} - \frac{x ^{9}}{162} + C

Solution steps

\int (\frac{x ^{4}}{12})^{2} d x

Apply Integration By Parts

: \frac{x ^{9}}{144} - \int \frac{x ^{8}}{18} d x

= \frac{x ^{9}}{144} - \int \frac{x ^{8}}{18} d x

\int \frac{x ^{8}}{18} d x = \frac{x ^{9}}{162}

= \frac{x ^{9}}{144} - \frac{x ^{9}}{162}

Add a constant to the solution

= \frac{x ^{9}}{144} - \frac{x ^{9}}{162} + C

\frac{4 t}{( 2 - 8 t ^{2} )}

\frac{( 1 + cos ^{2} ( x ) )}{cos ^{2} ( x )}

(e^{x})^{\frac{1}{2}}

\frac{1}{( 2 x + 1 ) ^{2}}

cos (2 - 3 x)

What is the integral of ((x^4)/(12))^2 ?
The integral of ((x^4)/(12))^2 is (x^9)/(144)-(x^9)/(162)+C