What is the integral of 1/((x^n)) ?

The integral of 1/((x^n)) is (x^{-n+1})/(-n+1)+C

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integral of 1/((x^n))

integral

\frac{1}{( x ^{n} )}

\frac{x ^{- n + 1}}{- n + 1} + C

Solution steps

\int \frac{1}{x ^{n}} d x

Apply the Power Rule

: \frac{x ^{- n + 1}}{- n + 1}

= \frac{x ^{- n + 1}}{- n + 1}

Add a constant to the solution

= \frac{x ^{- n + 1}}{- n + 1} + C

x^{2} (e^{x})^{3}

n^{2}

1 + 16 x^{2}

\frac{( e ^{2 x} )}{x}

2 x^{3} (e^{x})^{2}

What is the integral of 1/((x^n)) ?
The integral of 1/((x^n)) is (x^{-n+1})/(-n+1)+C