What is the tangent of f(x)=11-x^2 ?

The tangent of f(x)=11-x^2 is y=-2a_{0}x+11+a_{0}^2

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tangent of f(x)=11-x^2

tangent of

f (x) = 11 - x^{2}

y = - 2 a_{0} x + 11 + a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 11 - a_{0}^{2})

Find the slope of

f (x) = 11 - x^{2} : \frac{df ( x )}{d x} = - 2 x

Compute the slope of

f (x) = 11 - x^{2}

x = a_{0} : m = - 2 a_{0}

Find the line with slope m=

- 2 a_{0}

and passing through

(a_{0}, 11 - a_{0}^{2}) : y = - 2 a_{0} x + 11 + a_{0}^{2}

y = - 2 a_{0} x + 11 + a_{0}^{2}

40

x \to 4 π lim (e^{t a n (x)})

\frac{d}{d x} (a^{5 x})

f (x) = x^{3} + 4 x - 4, (1, 1)

\int_{0}^{0.5} (1 - x^{2})^{0.5} d x

What is the tangent of f(x)=11-x^2 ?
The tangent of f(x)=11-x^2 is y=-2a_{0}x+11+a_{0}^2