What is the integral of 2xcos(x^2) ?

The integral of 2xcos(x^2) is sin(x^2)+C

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integral of 2xcos(x^2)

integral

2 x cos (x^{2})

sin (x^{2}) + C

Solution steps

\int 2 x cos (x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x cos (x^{2}) d x

Apply u-substitution

: \int \frac{cos ( u )}{2} d u

= 2 \cdot \int \frac{cos ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 2 \cdot \frac{1}{2} sin (u)

Substitute back

u = x^{2}

= 2 \cdot \frac{1}{2} sin (x^{2})

Simplify

2 \cdot \frac{1}{2} sin (x^{2}) : sin (x^{2})

= sin (x^{2})

Add a constant to the solution

= sin (x^{2}) + C

\frac{sin ^{2} ( x )}{( 1 + sin ^{2} ( x ) )}

\frac{x ( x + 1 )}{2}

(\frac{1}{x}) (cos (x) - sin (x))

x cos (x) cos (2 x)

x^{- 6}