What is the integral of ((x+7))/((x+9)) ?

The integral of ((x+7))/((x+9)) is -2ln|x+9|+x+C

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integral of ((x+7))/((x+9))

integral

\frac{( x + 7 )}{( x + 9 )}

- 2 ln ∣ x + 9 ∣ + x + C

Solution steps

\int \frac{x + 7}{x + 9} d x

\frac{x + 7}{x + 9} = - \frac{2}{x + 9} + 1

= \int - \frac{2}{x + 9} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{2}{x + 9} d x + \int 1 d x

\int \frac{2}{x + 9} d x = 2 ln ∣ x + 9 ∣

\int 1 d x = x

= - 2 ln ∣ x + 9 ∣ + x

Add a constant to the solution

= - 2 ln ∣ x + 9 ∣ + x + C

sin (1 - x)

cos (y^{2})

\frac{1}{( d ^{2} + 1 ) cos ( x )}

sin (2 x + y)

f (x) = 55 - 4 x

What is the integral of ((x+7))/((x+9)) ?
The integral of ((x+7))/((x+9)) is -2ln|x+9|+x+C