What is the integral of ((4+12x))/4 ?

The integral of ((4+12x))/4 is 1/2 x(3x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((4+12x))/4

integral

\frac{( 4 + 12 x )}{4}

\frac{1}{2} x (3 x + 2) + C

Solution steps

\int \frac{4 + 12 x}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int 4 + 12 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{4} (\int 4 d x + \int 12 x d x)

\int 4 d x = 4 x

\int 12 x d x = 6 x^{2}

= \frac{1}{4} (4 x + 6 x^{2})

Simplify

\frac{1}{4} (4 x + 6 x^{2}) : \frac{1}{2} x (3 x + 2)

= \frac{1}{2} x (3 x + 2)

Add a constant to the solution

= \frac{1}{2} x (3 x + 2) + C

(e^{x})^{- 2}

\frac{x ^{2} + x + 1}{x}

\frac{1}{( x + 1 ) ^{2} + 1}

\frac{1}{( a ^{3} - 2 a )}

4 - ∣ x ∣

What is the integral of ((4+12x))/4 ?
The integral of ((4+12x))/4 is 1/2 x(3x+2)+C