What is the tangent of y=x+sqrt(x),(4,6) ?

The tangent of y=x+sqrt(x),(4,6) is y= 5/4 x+1

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tangent of y=x+sqrt(x),(4,6)

tangent of

y = x + x, (4, 6)

y = \frac{5}{4} x + 1

Solution steps

Find the slope of

y = x + x : \frac{d y}{d x} = 1 + \frac{1}{2 x}

Compute the slope of

y = x + x

(4, 6) : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, 6) : y = \frac{5}{4} x + 1

y = \frac{5}{4} x + 1

\int \frac{1}{tan ( v )} d v

\int_{0}^{8} \frac{1}{8 - x} d x

x^{2} arctan (3 x)

\frac{\partial}{\partial x} (e^{x - 1} cos (y))

\frac{d}{d x} (cos^{4} (sin^{3} (x)))

What is the tangent of y=x+sqrt(x),(4,6) ?
The tangent of y=x+sqrt(x),(4,6) is y= 5/4 x+1