What is the integral of 1/(x^{0.5)} ?

The integral of 1/(x^{0.5)} is 2sqrt(x)+C

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integral of 1/(x^{0.5)}

integral

\frac{1}{x ^{0.5}}

2 x + C

Solution steps

\int \frac{1}{x ^{0.5}} d x

Apply the Power Rule

: 2 x^{0.5}

= 2 x^{0.5}

Apply radical rule:

a^{\frac{1}{n}} = n a

= 2 x

Add a constant to the solution

= 2 x + C

x^{4} (a^{2} - x^{2})^{\frac{1}{2}}

tan (x) + x^{6} + e^{x}

\frac{1}{( 3 x ^{2} )}

\frac{( x ^{5} - 1 )}{x - 1}

\frac{x ^{3}}{( 1 + x ^{2} )}